(2)因为b1=a1=1,q=f(m)=2m/(m+3),

所以n∈N*且n≥2时,

bn=3/2f(bn-1)=3/2·(2b_(n-1))/(b_(n-1)+3),

bnbn-1+3bn=3bn-1,1/b_n -1/b_(n-1) =1/3,

所以数列{1/b_n }是以1为首项,1/3为公差的等差数列.

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